## College Physics (4th Edition)

The flux through one surface of the cube is $~1.7\times 10^4~V~m$
We can use Gauss' law to find the total flux through the cube: $\Phi = \frac{Q}{\epsilon_0}$ $\Phi = \frac{0.890\times 10^{-6}~C}{8.854\times 10^{-12}~F/m}$ $\Phi = 1.0\times 10^5~V~m$ By symmetry, the flux through each surface is $\frac{1}{6}$ of the total flux through the cube. We can find the flux through one surface: $\Phi' = \frac{1.0\times 10^5~V~m}{6} = 1.7\times 10^4~V~m$ The flux through one surface of the cube is $~1.7\times 10^4~V~m$