College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 16 - Problems - Page 614: 28


(a) The sodium ions flow into the cell. (b) $F = 1.6\times 10^{-12}~N$

Work Step by Step

(a) The electric field is directed into the cell. Since the charge on the sodium ions is positive, the force exerted on the ions will be directed in the same direction as the electric field. Therefore, the sodium ions flow into the cell. (b) We can find the force exerted on the sodium ion: $F = E~q$ $F = (1.0\times 10^7~N/C)(1.6\times 10^{-19}~C)$ $F = 1.6\times 10^{-12}~N$
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