College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 16 - Multiple-Choice Questions - Page 612: 4


The correct answer is: (a) $\frac{F}{2}$

Work Step by Step

We can write an expression for the original force: $F = \frac{k~q_1~q_2}{r^2}$ We can write an expression for the new force: $F' = \frac{k~(2q_1)~q_2}{(2r)^2} = \frac{1}{2}\times \frac{k~q_1~q_2}{r^2} = \frac{F}{2}$ The correct answer is: (a) $\frac{F}{2}$
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