## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 15 - Problems - Page 567: 5

#### Answer

(a) The temperature change of the paint would be $10.75~K$ (b) The amount of heat that flowed to the surroundings is $55,650~J$

#### Work Step by Step

(a) We can find the work done on the system in 5.00 min: $W = P~t = (448~W)(300~s) = 134,400~J$ We can find the temperature change: $\Delta T = \frac{134,400~J}{12,500~J/K} = 10.75~K$ The temperature change of the paint would be $10.75~K$ (b) We can find the change in internal energy of the paint: $\Delta U = (12,500~J/K)(6.3~K) = 78,750~J$ We can find the amount of heat that flowed to the surroundings: $Q = 134,400~J-78,750~J = 55,650~J$ The amount of heat that flowed to the surroundings is $55,650~J$

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