College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Multiple-Choice Questions - Page 533: 8


option c.

Work Step by Step

Thermal conductivity $∝ L/A ∝ L/d^2$ Thus, $L1/d1^2 = L2/d2^2$ => $L1/L2 = d1^2/d2^2$.
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