College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 500: 78


$v_{rms} = \sqrt{\frac{3~k~T}{m}}$

Work Step by Step

We can find the rms speed: $\overline{KE} = \frac{3}{2}~k~T$ $\frac{1}{2}m~v_{rms}^2 = \frac{3}{2}~k~T$ $v_{rms} = \sqrt{\frac{3~k~T}{m}}$
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