## College Physics (4th Edition)

The closest distance between nodes is: (c) $~\frac{2}{7} L$
For a pipe that is closed at one end, the wavelength is $\lambda_n = \frac{4L}{n}$ If the frequency of the standing wave is seven times the fundamental frequency, then $n=7$ and $\lambda_7 = \frac{4L}{7}$ Since there is a node at each half-cycle, the distance between each successive node is $\frac{\lambda_7}{2} = \frac{2L}{7}$ The closest distance between nodes is: (c) $~\frac{2}{7} L$