College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 12 - Multiple-Choice Questions - Page 462: 9


The closest distance between nodes is: (c) $~\frac{2}{7} L$

Work Step by Step

For a pipe that is closed at one end, the wavelength is $\lambda_n = \frac{4L}{n}$ If the frequency of the standing wave is seven times the fundamental frequency, then $n=7$ and $\lambda_7 = \frac{4L}{7}$ Since there is a node at each half-cycle, the distance between each successive node is $\frac{\lambda_7}{2} = \frac{2L}{7}$ The closest distance between nodes is: (c) $~\frac{2}{7} L$
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