College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 11 - Problems - Page 433: 82


The wavelength is $2.4~km$

Work Step by Step

We can find the speed of the waves: $v = \frac{d}{t} = \frac{180~km}{30.0~s} = 6.0~km/s$ On the graph, we can see that there are four cycles in $1.6~s$. We can find the period: $T = \frac{1.6~s}{4~cycles} = 0.40~s$ We can find the wavelength: $\lambda = \frac{v}{f}$ $\lambda = \frac{v}{1/T}$ $\lambda = v~T$ $\lambda = (6.0~km/s)(0.40~s)$ $\lambda = 2.4~km$ The wavelength is $2.4~km$
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