College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 11 - Problems - Page 429: 27


We can write the equation for this wave: $y(x,t) = (2.50~cm)~sin~[~(8.0~rad/m)~x - (2.90~rad/s)~t~]$

Work Step by Step

The maximum speed of a point on the string is $v_m = A~\omega$. Then the wave speed is $5A\omega$. We can find the wave number $k$: $v = \frac{\omega}{k}$ $k = \frac{\omega}{v}$ $k = \frac{\omega}{5~A~\omega}$ $k = \frac{1}{5~A}$ $k = \frac{1}{(5)(0.0250~m)}$ $k = 8.0~rad/m$ In general: $y(x,t) = A~sin(k~x-\omega~t)$ We can write the equation for this wave: $y(x,t) = (2.50~cm)~sin~[~(8.0~rad/m)~x - (2.90~rad/s)~t~]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.