Answer
(a) The amplitude is $3.5~cm$
(b) The wavelength is $6.0~cm$
Work Step by Step
(a) In general: $y(x,t) = A~sin(k~x-\omega~t)$
We can see from the equation that $A = 3.5~cm$
The amplitude is $3.5~cm$
(b) We can see from the equation that $k= \frac{\pi~rad}{3.0~cm}$
We can find the wavelength:
$\lambda = \frac{2\pi}{k}$
$\lambda = \frac{2\pi}{\pi~rad/3.0~cm}$
$\lambda = 6.0~cm$
The wavelength is $6.0~cm$
