College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 404: 103


The frequency of oscillation is $0.63~Hz$

Work Step by Step

We can find the period of a physical pendulum: $T = 2\pi~\sqrt{\frac{I_{support}}{mgL_{cm}}}$ $T = 2\pi~\sqrt{\frac{0.25~m^2}{(9.80~m/s^2)(0.40~m)}}$ $T = 1.587~s$ We can find the frequency: $f = \frac{1}{T}$ $f = \frac{1}{1.587~s}$ $f = 0.63~Hz$ The frequency of oscillation is $0.63~Hz$.
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