## College Physics (4th Edition)

The period of the pendulum is $2.5~s$
We can find the angular frequency $\omega$: $v_m = A~\omega$ $\omega = \frac{v_m}{A}$ $\omega = \frac{0.50~m/s}{0.20~m}$ $\omega = 2.50~rad/s$ We can find the period: $T = \frac{2\pi}{\omega}$ $T = \frac{2\pi}{2.50~rad/s}$ $T = 2.5~s$ The period of the pendulum is $2.5~s$.