Answer
(a) The period of vibration is $1.0\times 10^{-6}~s$
(b) The angular frequency is $6.3\times 10^6~rad/s$
Work Step by Step
(a) We can find the period of vibration:
$T = \frac{1}{f} = \frac{1}{1.0\times 10^6~Hz} = 1.0\times 10^{-6}~s$
The period of vibration is $1.0\times 10^{-6}~s$
(b) We can find the angular frequency:
$\omega = 2\pi~f = (2\pi)(1.0\times 10^6~Hz) = 6.3\times 10^6~rad/s$
The angular frequency is $6.3\times 10^6~rad/s$
