College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 397: 1


The vertical compression of the beam is $9.67\times 10^{-5}~m$

Work Step by Step

$Y = \frac{F/A}{\Delta L/L_0}$ $Y$ is Young's modulus $F$ is the force $A$ is the cross-sectional area $\Delta L$ is the change in length $L_0$ is the original length We can find the vertical compression: $\Delta L = \frac{F~L_0}{Y~A}$ $\Delta L = \frac{(5.8\times 10^4~N)(2.5~m)}{(200\times 10^9~N/m^2)(7.5\times 10^{-3}~m^2)}$ $\Delta L = 9.67\times 10^{-5}~m$ The vertical compression of the beam is $9.67\times 10^{-5}~m$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.