College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Section 1.9 - Graphs - Checkpoint - Page 17: 1.9

Answer

$k = 0.299~N/cm$ It is better to use the value obtained from the best-fit line because this value will be more accurate.

Work Step by Step

The first data point is $(0~N, 9.4~cm)$ The last data point is $(6.00~N, 29.5~cm)$ We can find the slope: $slope = \frac{\Delta L}{\Delta F} = \frac{29.5~cm-9.4~cm}{6.00~N-0~N} = 3.35~cm/N$ We can find $k$: $k = \frac{1}{slope} = \frac{1}{3.35~cm/N} = 0.299~N/cm$ It is better to use the value obtained from the best-fit line because this value will be more accurate.
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