## College Physics (4th Edition)

The left side and the right side of the equation do not have the same dimensions so the equation is incorrect. It seems that the correct equation should be $d = \frac{1}{2}at^2$
$d = \frac{1}{2}at$ We can use dimensional analysis to check this equation. The dimensions of the left side of the equation are [L]. The dimensions of the right side of the equation are $\frac{[L]}{[T^2]}\times [T] = \frac{[L]}{[T]}$ The left side and the right side of the equation do not have the same dimensions so the equation is incorrect. It seems that the correct equation should be $d = \frac{1}{2}at^2$