## College Physics (4th Edition)

$v = c~\sqrt{T}$, for some constant $c$ We can write an expression for $v_1$ and $T_1$: (equation 1): $v_1 = c~\sqrt{T_1}$ We can write an expression for $v_2$ and $T_2$: (equation 2): $v_2 = c~\sqrt{T_2}$ We can divide equation 2 by equation 1: $\frac{v_2}{v_1} = \frac{c~\sqrt{T_2}}{c~\sqrt{T_1}}$ $v_2 = \frac{v_1~\sqrt{T_2}}{\sqrt{T_1}}$ $v_2 = \frac{(475~m/s)~\sqrt{250.0~K}}{\sqrt{300.0~K}}$ $v_2 = 433.6~m/s$ The average speed is 433.6 m/s.