## College Physics (4th Edition)

The correct answer is (b) $kg\cdot m^2 \cdot s^{-2}\cdot K^{-1}$
$v = \sqrt{\gamma ~k_B ~T / m}$ Let $x$ be the units of $k_B$ $m/s = \sqrt{(x)(K)/kg}$ $m^2/s^2 = (x)(K)/kg$ $x = \frac{kg\cdot m^2}{s^2\cdot K} = kg\cdot m^2 \cdot s^{-2}\cdot K^{-1}$ The correct answer is (b) $kg\cdot m^2 \cdot s^{-2}\cdot K^{-1}$