College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Multiple-Choice Questions - Page 18: 5


The correct answer is (d) $1/\sqrt{2}$

Work Step by Step

The area of the original circle is $A = \pi r^2$ We multiply the radius $r$ by some factor $k$; The new radius is $kr$. The area of the new circle is $A_2 = \pi (kr)^2$ We know that $A_2 = \frac{A}{2}$ $\pi (kr)^2 = \frac{\pi r^2}{2}$ $k^2 \pi r^2 = \frac{\pi r^2}{2}$ $k^2 = \frac{1}{2}$ $k = \sqrt{\frac{1}{2}} = 1 / \sqrt{2}$ The correct answer is (d) $1/\sqrt{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.