Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 9 - Section 9.5 - Totally Inelastic Collisions - Example - Page 163: 9.9

Answer

The answer is below.

Work Step by Step

Using conservation of energy, we find: $\frac{1}{2}(\frac{mv}{m+M})^2 = gh \\ (\frac{mv}{m+M})^2 = 2gh \\ (\frac{mv}{m+M}) = \sqrt{2gh} \\ v = (\frac{m+M}{m})\sqrt{2gh} $
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