## Essential University Physics: Volume 1 (4th Edition)

Published by Pearson

# Chapter 9 - Section 9.5 - Totally Inelastic Collisions - Example - Page 162: 9.7

#### Answer

$49 \ m/s$

#### Work Step by Step

We find: $v_p = \frac{(m_p+m_c)v_c}{m_p} = (.16+6.4)(1.2)/.16 \approx 49 \ m/s$

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