Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 9 - Section 9.5 - Totally Inelastic Collisions - Example - Page 162: 9.7

Answer

$49 \ m/s$

Work Step by Step

We find: $v_p = \frac{(m_p+m_c)v_c}{m_p} = (.16+6.4)(1.2)/.16 \approx 49 \ m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.