## Essential University Physics: Volume 1 (4th Edition)

$743\times10^6 \ m$
The distance between the two is an average of $779 \times 10^9 m$. The sun weighs $1.989\times 10^{30} \ kg$, and Jupiter weighs $1.898 \times 10^{27}\ kg$. Thus, we use the equation for center of mass to find: $\frac{(1.898 \times 10^{27}\ kg)(779 \times 10^9 m)}{(1.989\times 10^{30})+(1.898 \times 10^{27}\ kg)}=743\times10^6 \ m$