Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 9 - Exercises and Problems - Page 173: 90

Answer

$743\times10^6 \ m$

Work Step by Step

The distance between the two is an average of $779 \times 10^9 m$. The sun weighs $1.989\times 10^{30} \ kg $, and Jupiter weighs $1.898 \times 10^{27}\ kg $. Thus, we use the equation for center of mass to find: $\frac{(1.898 \times 10^{27}\ kg)(779 \times 10^9 m)}{(1.989\times 10^{30})+(1.898 \times 10^{27}\ kg)}=743\times10^6 \ m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.