Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 9 - Exercises and Problems - Page 172: 60

Answer

$F=3mN$

Work Step by Step

As the rate of change of mass is given as: $\frac{dm}{dt}=\frac{12}{2}=6\frac{g}{s}$ Now we can find the force: $F=\frac{dp}{dt}$ $F=\frac{d}{dt}(mv)$ $\implies F=v\frac{dm}{dt}$ We plug in the known values to obtain: $F=50\times 6 \ dyne$ $F=3mN$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.