## Essential University Physics: Volume 1 (4th Edition)

$F=3mN$
As the rate of change of mass is given as: $\frac{dm}{dt}=\frac{12}{2}=6\frac{g}{s}$ Now we can find the force: $F=\frac{dp}{dt}$ $F=\frac{d}{dt}(mv)$ $\implies F=v\frac{dm}{dt}$ We plug in the known values to obtain: $F=50\times 6 \ dyne$ $F=3mN$