Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Section 7.4 - Nonconservative Forces - Example - Page 123: 7.6

Answer

$ \frac{1}{2}kx_0^2 = \mu mgd$

Work Step by Step

We know that the block will stop when all of the spring energy becomes mechanical energy, meaning that it will be lost to friction. Thus, we find: $ \frac{1}{2}kx_0^2 = F_f \times d$ $ \frac{1}{2}kx_0^2 = \mu F_n \times d$ $ \frac{1}{2}kx_0^2 = \mu mgd$
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