Answer
1.7 meters
Work Step by Step
We know from the situation that:
$mgh = \frac{1}{2} kx^2$
Thus, we find:
$ h = \frac{kx^2}{2mg}$
$ h = \frac{140(.11)^2}{2(.05)(9.81)}=1.7m$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 7 - Section 7.3 - Conservation of Mechanical Energy - Example - Page 121: 7.5
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