Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Section 7.2 - Potential Energy - Example - Page 118: 7.2


.86 meters

Work Step by Step

We simplify the equation for spring energy: $U = \frac{1}{2}kx^2 \\ x = \sqrt{\frac{2U}{k}} \\ x = \sqrt{\frac{2(44,000)}{120,000}}= .86m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.