Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Section 7.2 - Potential Energy - Example - Page 118: 7.2

Answer

.86 meters

Work Step by Step

We simplify the equation for spring energy: $U = \frac{1}{2}kx^2 \\ x = \sqrt{\frac{2U}{k}} \\ x = \sqrt{\frac{2(44,000)}{120,000}}= .86m$
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