Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Section 6.5 - Power - Example - Page 106: 6.7

Answer

a) $97 \ W$ b) $11,000 \ W$

Work Step by Step

We know that the average power is equal to the change in work over the change in time. Thus, we find: a) $P_{avg} = \frac{1300 \times 9.81 \times 55}{2 \times 3600} = 97 \ W$ b) $P_{avg} = \frac{1300 \times 9.81 \times 1500}{.5 \times 3600} = 11,000 \ W$
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