Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Section 6.3 - Forces That Vary - Example - Page 101: 6.4

Answer

15,000 Joules

Work Step by Step

If the length doubled, it has been increased by 11 meters. We know that work equals change in Spring energy in this case, so we find: $ W = \frac{1}{2}kx^2 = \frac{1}{2}(250)(11)^2 \approx 15,000 J$
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