Answer
15,000 Joules
Work Step by Step
If the length doubled, it has been increased by 11 meters. We know that work equals change in Spring energy in this case, so we find:
$ W = \frac{1}{2}kx^2 = \frac{1}{2}(250)(11)^2 \approx 15,000 J$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 6 - Section 6.3 - Forces That Vary - Example - Page 101: 6.4
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