Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 112: 91

Answer

The force is 35 times the weight of the leg.

Work Step by Step

We first find the energy the leg has before it hits the ground: $E=mgh=(8)(9.81)(.7)\approx 55J$ We know that the force is equal to the work done over the distance. Thus, we find: $F = \frac{55J}{.02m} = 2,749 \ N$ Thus, the force is 35 times the weight of the leg.
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