## Essential University Physics: Volume 1 (4th Edition) Clone

We first find the energy the leg has before it hits the ground: $E=mgh=(8)(9.81)(.7)\approx 55J$ We know that the force is equal to the work done over the distance. Thus, we find: $F = \frac{55J}{.02m} = 2,749 \ N$ Thus, the force is 35 times the weight of the leg.