## Essential University Physics: Volume 1 (4th Edition)

a) $5.2 \ m/s^2$ b) $532 \ N$
We first break the forces into x and y components: $F_{nx} + F_{gx} = ma_x$ $F_{ny} + F_{gy} = ma_y$ We see that the x-component can be simplified as follows: $F_{nx} + F_{gx} = ma_x$ $mgsin\theta= ma_x$ $gsin\theta= a_x$ Thus: $a_x = (9.8)(sin32^{\circ}) = 5.2 \ m/s^2$ We use the y component to find the normal force: $F_{ny} + F_{gy} = ma_y$ $F_n = mgcos\theta$ $F_n = 65(9.81)(cos32^{\circ})=532 \ N$