Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Section 5.1 - Using Newton’s Second Law - Example - Page 75: 5.1

Answer

a) $5.2 \ m/s^2$ b) $532 \ N$

Work Step by Step

We first break the forces into x and y components: $F_{nx} + F_{gx} = ma_x$ $F_{ny} + F_{gy} = ma_y$ We see that the x-component can be simplified as follows: $F_{nx} + F_{gx} = ma_x$ $ mgsin\theta= ma_x$ $ gsin\theta= a_x$ Thus: $a_x = (9.8)(sin32^{\circ}) = 5.2 \ m/s^2$ We use the y component to find the normal force: $F_{ny} + F_{gy} = ma_y$ $F_n = mgcos\theta $ $F_n = 65(9.81)(cos32^{\circ})=532 \ N $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.