Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 91: 39

Answer

Please see the work below.

Work Step by Step

We know that $a=gsin(\theta)$ $a=9.8sin(35)=5.621\frac{m}{s^2}$ Now we can find the distance as $d=\frac{v^2}{2a}$ $d=\frac{(2.2)^2}{(2)(5.621)}=0.43m$
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