## Essential University Physics: Volume 1 (4th Edition)

We know that $a=gsin(\theta)$ $a=9.8sin(35)=5.621\frac{m}{s^2}$ Now we can find the distance as $d=\frac{v^2}{2a}$ $d=\frac{(2.2)^2}{(2)(5.621)}=0.43m$