## Essential University Physics: Volume 1 (4th Edition) Clone

We know that $a=\frac{F}{m}$ We plug in the known values to obtain: $a=\frac{65000}{1300}=50\frac{m}{s^2}$ The distance covered by the bumper is given as $d=\frac{v^2}{2a}$ We plug in the known values to obtain: $d=\frac{(\frac{10}{3.6})^2}{2(50)}=0.077m$