#### Answer

Please see the work below.

#### Work Step by Step

We know that
$a=\frac{F}{m}$
We plug in the known values to obtain:
$a=\frac{65000}{1300}=50\frac{m}{s^2}$
The distance covered by the bumper is given as
$d=\frac{v^2}{2a}$
We plug in the known values to obtain:
$d=\frac{(\frac{10}{3.6})^2}{2(50)}=0.077m$