# Chapter 3 - Section 3.6 - Uniform Circular Motion - Example - Page 47: 3.7

$1.52 \ h$

#### Work Step by Step

Using the equation for period, we find: $T = \sqrt{\frac{4\pi^2r}{a}}$ $T = \sqrt{\frac{4\pi^2(6.77\times10^6)}{8.73}}=5532\ s= 1.52 \ h$

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