Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Section 3.5 - Projectile Motion - Example - Page 42: 3.4

Answer

$18.25 \ m$

Work Step by Step

We first must find the change in time: $\Delta t = \sqrt{\frac{(2)(1.7)}{9.81}}=.589 \ s$ Using this, we find that the change in x is: $ x= (31)(.589)=18.25 \ m$
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