Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Section 3.3 - Velocity and Acceleration Vectors - Example - Page 39: 3.2

Answer

1.4 hours

Work Step by Step

We know the following equation for the velocity: $\vec{v} \prime = v'cos(\theta) \hat{i} + v'sin(\theta)\hat{j}$ Adding in the wind, we find the x-component: x: $v'cos\theta + V = 0 $ Solving this, we find: $\theta=cos^{-1}(\frac{-V}{v'})=cos^{-1}(\frac{-190}{960}) =101^{\circ}$ We use the y component, which is $v=v'sin\theta$, to find: $v = 960 sin(101^{\circ})=941 \ km/h$ Using the equation for change in time, we find: $\Delta t = \frac{1290}{941}=1.4h$
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