Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 33: 90


Please see the work below.

Work Step by Step

We know that $t=\sqrt{\frac{2h}{g}}$ $t=\sqrt{\frac{2(0.196)}{9.8}}=0.2s$ As there are four drops at 0.2 seconds, the number of drops per second can be determined as $N=\frac{4}{0.2}=20 drops$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.