Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 30: 15

Answer

$7.38 \frac{m}{sec}$

Work Step by Step

As we know that $= \frac{total distance traveled}{total time taken}$ So from the given data $= \frac{1.5Km + 40Km + 10Km}{1 hour 56 minutes and 16 sec}$ converting into standard units we get, $= \frac{1500m + 40000m + 10000m}{6976sec}$ Or $= \frac{51500m}{6976sec}$ solving we get, $= 7.38\frac{m}{sec}$
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