## Essential University Physics: Volume 1 (4th Edition)

Published by Pearson

# Chapter 19 - Exercises and Problems - Page 361: 11

#### Answer

a) 26.8% b) 7.05% c) 77.0%

#### Work Step by Step

We know that the maximum efficiency is given by: $$e_{max}=1- \frac{T_c}{T_h}$$ Where $T_c$ is the cold temperature, $T_h$ is the hot temperature, and $e_{max}$ is the maximum efficiency. Now, plug in the given values, remembering to convert to Kelvin. This means that the efficiencies are: a) 26.8% b) 7.05% c) 77.0%

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