Essential University Physics: Volume 1 (4th Edition) Clone

We adjust equation 18.11b to obtain: $\frac{V_z{max}}{V_{min}} = (\frac{T_{max}}{T_{min}})^{1/(\gamma-1)}$ $\frac{V_{max}}{V_{min}} = (\frac{773}{293})^{1/(1.4-1)}\approx 11$