Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Section 18.2 - Thermodynamic Processes - Example - Page 335: 18.3

Answer

11

Work Step by Step

We adjust equation 18.11b to obtain: $\frac{V_z{max}}{V_{min}} = (\frac{T_{max}}{T_{min}})^{1/(\gamma-1)}$ $\frac{V_{max}}{V_{min}} = (\frac{773}{293})^{1/(1.4-1)}\approx 11$
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