Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 343: 68


$W= 2.23 \times 10^{-9}\ J$

Work Step by Step

We know that 4.5 mL is the same as $4.5 \times 10^{-6}m^3$. Thus, we find: $W = \int_0^{4.5 \times 10^{-6}} (10v^3 - 67v^2+220v )dv$ $W= 2.23 \times 10^{-9}\ J$
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