## Essential University Physics: Volume 1 (4th Edition)

$W= 2.23 \times 10^{-9}\ J$
We know that 4.5 mL is the same as $4.5 \times 10^{-6}m^3$. Thus, we find: $W = \int_0^{4.5 \times 10^{-6}} (10v^3 - 67v^2+220v )dv$ $W= 2.23 \times 10^{-9}\ J$