Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 17 - Section 17.3 - Thermal Expansion - Example - Page 321: 17.5

Answer

.274 Liters are lost.

Work Step by Step

We find the change in volume of the can and the gas to find: $\Delta V_{can}=\beta V\Delta T=(3)(12\times10^{-6})(20)(15)=.0108L$ $\Delta V_{gas}=\beta V\Delta T=(95\times10^{-5})(20)(15)=.285L$ Thus, .274 Liters are lost.
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