## Essential University Physics: Volume 1 (4th Edition)

a) We use the ideal gas law to find: $p_f = (1\times 10^5 Pa)(373K)/(293K)=1.3\times10^5 Pa$ b) Once again, we use unit conversions and the ideal gas law to find: $n = \frac{(1\times10^5Pa)(3\times10^{-3}m^3)}{(8.314J/Kmol)(373K)}=.1 mol$ c) Once again, we use unit conversions and the ideal gas law to find: $p = \frac{.1\times 8.314\times293}{3\times10^{-3}}=.8 \times 10^5 Pa$