Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Section 16.2 - Heat Capacity and Specific Heat - Example - Page 299: 16.2

Answer

26 degrees Celsius

Work Step by Step

We simplify equation 16.4 to find: $0 = m_wc_w(T-T_w) + m_pc_p(T-T_p)$ We solve for T and plug in the given values to find: $T = \frac{m_pc_pT_p + m_wc_wT_w}{m_pc_p + m_wc_w} = 26\ C$
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