## Essential University Physics: Volume 1 (4th Edition)

We know that the temperature is given by: $\frac{P}{4 \pi e R^2 \sigma}$ We plug in the known values to find: $T = (\frac{34,000}{.341425* 5.7* 10^{4}})^{1/4}*10^3$ $T=1150 K$