Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Section 15.2 - Hydrostatic Equilibrium - Example - Page 277: 15.2


490 N

Work Step by Step

We use the known equations to obtain: $mg = pA_2$ $mg = p \pi R_2^2$ $mg = \frac{F_1}{\pi R_1^2} \pi R_2^2$ $F_1 = mg (\frac{R_1}{R_2})^2$ $F_1 = (3200)(9.81) (\frac{15}{120})^2=490 \ N$
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