## Essential University Physics: Volume 1 (4th Edition)

We use the known equations to obtain: $mg = pA_2$ $mg = p \pi R_2^2$ $mg = \frac{F_1}{\pi R_1^2} \pi R_2^2$ $F_1 = mg (\frac{R_1}{R_2})^2$ $F_1 = (3200)(9.81) (\frac{15}{120})^2=490 \ N$