Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Exercises and Problems - Page 292: 79

Answer

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Work Step by Step

We know that the maximum load is equal to quantity of the difference between the cross sectional area of the ship and that of the triangle with height $h_0$ multiplied by the length of the ship, L, and the density of water, $\rho$. Thus, we find: $ A = h^2 tan \theta$ This means: $m = \rho L (h_0^2 - h_1^2)tan \frac{\theta}{2}$
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