## Essential University Physics: Volume 1 (4th Edition) Clone

We use the equation that relates the decibel level to intensity to find: $\beta_1 - \beta_2 = 10logP_2-10logP_1$ $\beta_1 - \beta_2 = 10log\frac{P_2}{P_1}$ $\frac{\beta_1 - \beta_2}{10} = log\frac{P_2}{P_1}$ $\frac{P_2}{P_1} = 10^{\frac{\beta_1 - \beta_2}{10}}$ $\frac{P_2}{P_1} = 10^{\frac{60 -75}{10}}$ $\frac{P_2}{P_1} = .032$