Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Section 14.4 - Sound Waves - Example - Page 258: 14.4

Answer

.032

Work Step by Step

We use the equation that relates the decibel level to intensity to find: $\beta_1 - \beta_2 = 10logP_2-10logP_1$ $\beta_1 - \beta_2 = 10log\frac{P_2}{P_1}$ $\frac{\beta_1 - \beta_2}{10} = log\frac{P_2}{P_1}$ $\frac{P_2}{P_1} = 10^{\frac{\beta_1 - \beta_2}{10}}$ $\frac{P_2}{P_1} = 10^{\frac{60 -75}{10}}$ $\frac{P_2}{P_1} = .032 $
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