Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Section 14.3 - Waves on a String - Example - Page 255: 14.2

Answer

110 Newtons

Work Step by Step

We find: $F = \mu v^2 = (\frac{m}{L})(\frac{L}{t})^2 = \frac{mL}{t^2} = \frac{(5)(43)}{1.4^2} \approx 110 \ N$
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