Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 270: 15

Answer

The answer is below.

Work Step by Step

We use the equation for wavelength to find: a) $\lambda= \frac{1500m/s}{8\times10^6Hz}=1.9\times10^{-4}m$ b) $\lambda= \frac{1500m/s}{3.5\times10^6Hz}=4.3\times10^{-4}m$
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