Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Section 13.5 - Energy in Simple Harmonic - Example - Page 240: 13.5

Answer

$ v = \frac{\omega A}{\sqrt{2}}$

Work Step by Step

We find: $ \frac{1}{2}mv^2 = \frac{1}{2}(\frac{1}{2}m\omega^2A^2)$ $ \frac{1}{2}mv^2 =(\frac{1}{4}m\omega^2A^2)$ $ v = \frac{\omega A}{\sqrt{2}}$
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